Here you can find the meaning of The area of a rectangular field is 2000 sq.m and itsperimeter is 180m. The length and breadth area)(205m, 80m)b)(50m, 40m)c)(40m, 50m)d)noneCorrect answer is option 'B'. Form a quadratic equation by taking the length of the field as x and solve it to find the length and breadth of the field. Can you explain this answer? covers all topics & solutions for CA Foundation 2023 Exam.įind important definitions, questions, meanings, examples, exercises and tests below for The area of a rectangular field is 2000 sq.m and itsperimeter is 180m.
Information about The area of a rectangular field is 2000 sq.m and itsperimeter is 180m. The Question and answers have been prepared
Can you explain this answer? for CA Foundation 2023 is part of CA Foundation preparation. The area of a rectangular field is 2000 sq.m and itsperimeter is 180m. Therefore, the length and breadth of the rectangular field are 50m and 40m respectively. Now, we can use equation (3) to find the corresponding values of y: We can solve this equation using the quadratic formula: Substituting equation (3) in equation (1), we get: We can solve these equations simultaneously to find the values of x and y. We have two equations (1) and (2) and two variables (x and y). We know the area of the rectangle is given by:Īlso, we know that the perimeter of the rectangle is given by: You can also now also factorise to get (x - 2)(x + 3) which might be another question in an exam situation.Let's assume that Length of the rectangular field is 'x' meters and Breadth is 'y' meters. We disregard the negative number because you cannot have a negative measurement in real life. Just plug the coefficients into the general formula, together with the value for the discriminant, which you found earlier.įinally, here are the two solutions for x. This is the value of the discriminant part. Therefore, it will have real roots, as opposed to imaginary roots had the number been negative. In this case, it is a positive number 400. This is the bit under the square root sign of the general formula. You always start by calculating the discriminant part. In exam conditions, you may have to solve this equation, in which case you might have to use the general formula for solving quadratic equations. As you can see, we now have a quadratic equation, which is the answer to the first part of the question. We are algebraically subtracting 24 on both sides, so the RHS becomes zero. In this step, we bring the 24 to the LHS. Since we know the expressions for A and B, we can plug them into the formula A + B = 24 as shown above. You then simply multiply each term in the brackets by x as shown above. The length is (4x+1), and the width is x, making it (4x+1) × x. The area of rectangle B is also its length multiplied by its width. The area of rectangle A is its length multiplied by its width, or 3 × x. The areas of the two rectangles add up to 24 obviously. Start by writing this expression shown above.
If the total area of the building, shaded in yellow, is 24 m² show the following formula. It is a six-sided shape where all the corners are right angles. Here is a floor plan of a building with the following dimensions.
0 kommentar(er)
